SSC CHSL 6 Dec 2015 Shift 2 Paper

© examsiri.com

Question : 143 of 200

Marks: +1, -0

If

1^3+2^3+.......10^3=3025

, then the value of

2^3+4^3....+20^3

is:

5060
12100
24200
7590

Solution:

Given :

1^3+2^3+.......10^3=3025

-----(i)
To find :

2^ 3 + 4 ^3 + .......... + 20^ 3

=

(2 × 1) ^3 + (2 × 2) ^3

+ .......... + (2 × 10)^ 3

=

(8 × 1 ^3) + (8 × 2 ^3)

+ ............ + (8 × 10^3 )

=

8 × (1 ^3 + 2 ^3

+ ...............+ 10^3 )

Substituting value from equation (i), we get :
= 8 × 3025 = 24200

© examsiri.com

Go to Question:

Prev Question

Next Question