If \alpha+\beta=90^\circ then the expression \tan\alpha+Sin+2\alpha+Sin^2\beta is equal to: \tan\beta

SSC CHSL 6 Dec 2015 Shift 2 Paper

Question : 139 of 200

Marks: +1, -0

α+β=90°

then the expression

tanα+Sin+2α+Sin^2β

is equal to:

t a n β

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