SSC CHSL 6 Dec 2015 Shift 2 Paper

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Question : 128 of 200

Marks: +1, -0

If

Sin 2θ = √3/2

then the value of

Sin3θ

is equal to : (Take 0 ° ≤ θ ≤ 90 )

0
$√3/2$
1
$1/2$

Solution:

Given :

Sin 2θ = √3/2

⇒

Sin 2θ = sin(60 °)

⇒

2θ = 60°

⇒

θ =60/ 2 =30°

To find :

sin 3θ

=

sin(3 × 30 °)

=

sin(90°) = 1

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