SSC CHSL 6 Dec 2015 Shift 2 Paper

Question : 117 of 200

Marks: +1, -0

A hemispherical bowl has internal radius of 6 cm. The internal surface area would be: (take π − 3.14)

Solution:

Radius of bowl = 6 cm
Surface area of hemisphere =

3πr^2

2 × 3.14 × (6)^2

2 × 113.04 = 226.08 cm^2

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