SSC CHSL 6 Dec 2015 Shift 1 Paper

Question : 149 of 200

Marks: +1, -0

The sides of a triangle are in the ratio of 7:9:12 The difference between the lengths of largest and smallest sides is 15 cm. The length of the largest side would be:

36 cm
12 cm
60 cm
24 cm

Validate

Solution:

Let the sides of the triangle be

7x,9x,12x

cm respectively.
⇒ Difference between the lengths of largest and smallest sides =

12x − 7x = 15

⇒

5x = 15

⇒

x = 15 /5 =3

∴ Largest side

=12×3=36 cm

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