SSC CHSL 6 Dec 2015 Shift 1 Paper

Question : 146 of 200

Marks: +1, -0

In ∆ABC, the internal bisectors of ∠B and ∠C meet at point D. If ∠A= 80° , then ∠BDC is of:

Solution:

Given : D is the incentre of ∆ABC and ∠BAC = 80°
To find : ∠BDC = θ = ?
Incentre of a triangle =

90°+∠A/2

⇒

θ = 90 °+ 80°/2

⇒

θ = 90 °+ 40°

⇒

θ = 130°

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