SSC CHSL 6 Dec 2015 Shift 1 Paper

Question : 139 of 200

Marks: +1, -0

The centroid of an equilateral triangle ABC is G and AB=10 cm. The length of AG (in cm)

Solution:

G is the centroid of ∆ ABC and AB = 10 cm.
Also, a centroid divides the median in the ratio =

AG : GD = 2 : 1

Now, median AD =

√3/2×10=5√3

cm
∴ AG =

2/(2+1)×5√3

10√3/3

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