SSC CHSL 6 Aug 2021 Shift 1 Paper

Given number $34\mathit{k}56\mathit{k}$ is divisible by 6 . So it must be divisible by 2 and 3 (both are factor of 6).
Divisibility rule of $2\to$ The last digit must be even or 0 .
So, it may be $0,2,4,6$ and 8 Divisibility rule of $3\to$ The sum of all digits must be divisible by 3 .
$\therefore$ Sum of digits
$=3+4+\mathit{k}+5+6+\mathit{k}$
$=18+2\mathit{k}$
For $\mathit{k}=3,6$ and 9 , given number is divisible by 3 .
But here only 6 is even value of $\mathit{k}$.
$\therefore \mathit{k}=6$
$\therefore$ Largest value of $\mathit{k}=6$.