SSC CHSL 5 Mar 2018 Shift 3 Paper

Section: English Language

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Question : 24 of 100

Marks: +1, -0

△ABC is right angled at B. If m∠c = 60° , then find the value of (cot A −

1/2

) ?

$-1/√3$
$(3− √2)/3 √$
$(2 √3−1)/2$
$( √2− √3)/√6$

Solution:

Given : ∆ ABC is a right angied at B and ∠C = 60°
⇒ ∠A = 30°
⇒

cotA = cot(30°) = √3

To find :

(\cot A − 1/2 )

=

√3 − 1/2

=

(2 √3−1)/2

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