SSC CHSL 5 Mar 2018 Shift 1 Paper

Section: English Language

Question : 1 of 100

Marks: +1, -0

What is the least number that can be multiplied to 69120 to make it a perfect cube?

Solution:

Prime factorization of

69120 = 2^ 9 × 3 ^3 × 5

For the number to be a perfect cube, all the exponents must be multiples of 3, thus the above number must be multiplied with

5^2 = 25

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