SSC CHSL 5 Aug 2021 Shift 3 Paper

Section: Quantitative Aptitude

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Question : 72 of 100

Marks: +1, -0

In a circle,

A B

and

D C

are two chords. When

A B

and

D C

are produced, they meet at

P

.
If

P C=2.8 {cm}, P B=3.15 {cm}

and

A B=3.85 {cm}

, then

C D=

?

$5.075 {cm}$
$4.175 {cm}$
$6.975 {cm}$
$7.875 {cm}$

Solution:

Given,

By intersecting secants theorem,

P B × P A \;\; =P C × P D

⇒ 3.15 ×(3.15+3.85)

\;\; =(2.8) ×(2.8+C D)

⇒ \;\; 3.15 × 7 \;\; =2.8 ×(2.8+C D)

∴ C D=7.875-2.8 \;\; =5.075 {cm}

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