SSC CHSL 5 Aug 2021 Shift 3 Paper

Section: Quantitative Aptitude

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Question : 63 of 100

Marks: +1, -0

A chord

P Q

of a circle

C_{1}

of radius

9.25 {cm}

touches another circle

C_{2}

that is concentric to

C_{1}

and the radius of

C_{2}

is

3 {cm}

. What is the length (in

{cm})

of

P Q

?

12
$19.5 \;\;$
$17.5$
15

Solution:

Given,

∴ \ln △ M O Q, O Q^{2}=O M^{2}+M Q^{2}

\;\; [ ∵

by Pythagoras

]

⇒ \;\; M Q^{2}=(9.25)^{2}-(3)^{2}=76.5625

M Q=√{76.5625}=8.75 {cm}

∴

Length of chord

P Q=8.75 × 2=17.5 {cm} .

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