SSC CHSL 5 Aug 2021 Shift 3 Paper

According to the question,
A number is divisible by 3 if the sum of the digit of that number is divisible by 3 .

$=15+\mathit{x}+\mathit{y}$
Now, the possible values of $\mathit{x}$ and $\mathit{y}$ are
$\mathit{x}=1,\mathit{y}=2$ and $\mathit{x}=2,\mathit{y}=1$
A number is divisible by 7 if the difference between twice the digit at ones place and the number formed by other digits is either zero or a multiple of 7 .
Now, last two digit $=\mathit{x}\mathit{y}=21\times 2=42$
Now, difference $=672-42=630$,
Which is divisible by 7 .


$=12+5=17$