SSC CHSL 4 Mar 2018 Shift 1 Paper

Section: General Awareness

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Question : 79 of 100

Marks: +1, -0

Determine the value 'x' of if x =

{(943+864)^2 −(943−864)^ 2}/(1886×1728)

1
4
79
1789

Solution:

Expression :

x = {(943+864)^2 −(943−864)^ 2}/(1886×1728)

Using,

a^2-b^2=(a+b)(a-b),

where

a=(943 + 864)

and

b = (943 − 864)

={[(943+864)+(943−864)]×[(943+864)−(943−864)]}/(1886×1728)

=

{(943+943)×(864+864)}/(1886×1728)

=

{(1886)×(1728)}/(1886×1728)=1

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