SSC CHSL 4 Aug 2021 Shift 1 Paper

Section: Quantitative Aptitude

Question : 63 of 100

Marks: +1, -0

One-quarter of a circular pizza of diameter

28 {cm}

was removed from the whole pizza. What is the perimeter (in

{cm}

) of the remaining pizza? (Take

π=\;{22}/{7}

)

Solution:

Given,

Diameter

=28 {cm}

Since, one quarter is removed.

∴

Total perimeter of the remaining pizza

\;\; =\;{3 π r}/{2}+2 r=3 × \;{22}/{7} × \;{14}/{2}+2 × 14

\;\; =66+28=94 {cm}

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