SSC CHSL 4 Aug 2021 Shift 1 Paper

Section: Quantitative Aptitude

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Question : 53 of 100

Marks: +1, -0

In a

△ A B C, ∠ B A C=90^{∘}

and

A D

is perpendicular to

B C

. If

A D=8.4 {cm}

and

B D=4.8 {cm}

, then the length of

B C

is

$19.5 {cm}$
$15 {cm}$
$18 {cm}$
$18.5 {cm}$

Solution:

Given,
We know that, in

△ A B C

,

A D^{2} \;\; =B D × D C

∴ D C \;\; =\;{8.4 × 8.4}/{4.8}

\;\; =14.7 {cm}

∴ B C \;\; =B D+D C

\;\; =4.8+14.7

\;\; =19.5 {cm}

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