If 2x ^2 + 2y^ 2 = 4a, then find the value of {2a} /{x^2-a}+ \frac{2a}{y^2-a}

SSC CHSL 24 Mar 2018 Shift 2 Paper

Section: English Language

Question : 4 of 100

Marks: +1, -0

2x ^2 + 2y^ 2 = 4a

, then find the value of

{2a} /{x^2-a}+ {2a}/{y^2-a}

Solution:

Given :

2x ^2 + 2y^ 2 = 4a

⇒

x^2+y^2=2a

-----------(i)
To find :

{2a} /{x^2-a}+ {2a}/{y^2-a}

2a(1/ {x ^2−a} + 1 /{y^2 −a} )

2a({(x^2 +y^2 )−2a}/ {(x ^2−a)(y^2 −a) })

Substituting value from equation (i), we get :
=

2a ×{2a−2a} /{(x ^2−a)(y^2 −a)}

2a × 0 = 0

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