SSC CHSL 24 Mar 2018 Shift 2 Paper

Let weight of P, Q and T be $\mathit{x},\mathit{y},\mathit{z}$ kg respectively.
Average weight of P and Q = $\frac{\mathit{x}+\mathit{y}}{2}=38$
⇒ $\mathit{x}+\mathit{y}=76$ ------------(i)
Similarly, $\mathit{x}+\mathit{y}+\mathit{z}=147$ -----------(ii)
Subtracting equation (i) from (ii), we get :
⇒ $\mathit{z}=147-76=71$
∴ Weight (in kg) of coach = 71 kg