SSC CHSL 20 Dec 2015 Shift 2 Paper

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Question : 147 of 200

Marks: +1, -0

If

11√n=√112+√343

, then the value of n is

13
7
11
3

Solution:

Expression :

11√n=√112+√343

⇒

11√n=√{16×7}+√{7×7×7}

⇒

11 √n = 4 √7 + 7 √7

⇒

11√ n = 11√ 7

⇒

√n =√ 7

⇒

n = 7

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