SSC CHSL 20 Dec 2015 Shift 2 Paper

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Question : 125 of 200

Marks: +1, -0

The expression

√{{1+sin θ}/ {1-sin θ}} +√{{1-sin θ }/{1+sin θ}}

is equal to

2 sec θ
2 tan θ
${2 (1−sin θ)}/{cos θ}$
2 sin θ

Solution:

Expression :

√{{1+sin θ}/ {1-sin θ}} +√{{1-sin θ }/{1+sin θ}}

=

{(√ {1+sinθ})^2+(√ {1-sinθ})^2}/{(√{1−sinθ}) (√ {1+sinθ} ) }

=

{(1+sinθ)+(1−sinθ)}/√{1−sin ^2θ}

=

2/{cosθ }= 2secθ

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