SSC CHSL 20 Dec 2015 Shift 1 Paper

Question : 23 of 200

Marks: +1, -0

A was twice as old as B, two years ago. If the difference in their ages be 2 years, find A’ s age.

Solution:

Let B's age two years ago =

x

years
⇒ A's age 2 years ago =

2x

years
⇒ Difference in age (remains constant) =

2x − x = 2

⇒

x = 2

∴ A's present age =

2(2)+2=6

years

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