SSC CHSL 20 Dec 2015 Shift 1 Paper

Given height of the prism = 8 cm .........(1)
Area of the base,
⇒ $\frac{\mathit{b}}{4}\sqrt{4{\mathit{a}}^2-{\mathit{b}}^2}$ (here a = 5, b = 6)
$\frac{6}{4}\sqrt{4{\left(5\right)}^2-6^2}$
$\frac{3}{2}\sqrt{64}=12$ .......(2)
Volume of the part = Area of the base x height of the prism
Substitute equation (1) and (2) in the above equation
Volume of the part = 12 x 8 = 96 cm
Hence, option D is the correct answer.