SSC CHSL 19 Mar 2020 Shift 2 Paper

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Question : 53 of 100

Marks: +1, -0

If

x^{4}+{1}/{x^{4}}=14159

, then the value of

x+{1}/{x}

is

9
12
10
11

Solution:

Given,

x^{4}+{1}/{x^{4}}=14159

⇒

x^{4}+{1}/{x^{4}}+2=14159+2=14161

⇒

(x^{2}+{1}/{x^{2}})^{2}=14161=(119)^{2}

⇒

x^{2}+{1}/{x^{2}}=119

⇒

x^{2}+{1}/{x^{2}}+2=119+2=121

⇒

(x^{2}+{1}/{x})^{2}=121

⇒

(x+{1}/{x})=\√{121}=11

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