SSC CHSL 19 Mar 2020 Shift 1 Paper

© examsiri.com

Question : 70 of 100

Marks: +1, -0

If

\Δ\ABC

is a right angled triangle with

\∠\ABC=90°

, and

\AC=10 {\cm}

,

\BC=8 {\cm}

, then the length of AB is

$12 {\cm}$
$2 {\cm}$
$18 {\cm}$
$6 {\cm}$

Solution:

Given,

Since,

\Δ \ABC

is a right-angle-triangle.
∴

\AC^{2}=\AB^{2}+\BC^{2}

[\∵

by Pythagoras theorem]
⇒

\AB^{2}=\AC^{2}-\BC^{2}

=(10)^{2}-(8)^{2}

=100-64=36

\AB=\√{36}=6 {\cm}

© examsiri.com

Go to Question:

Prev Question

Next Question