SSC CHSL 19 Mar 2020 Shift 1 Paper

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Question : 34 of 100

Marks: +1, -0

The sum of a number and its reciprocal is

{17}/{4}

. Find the numbers.

4 and ${1}/{4}$
3 and ${1}/{3}$
5 and ${1}/{5}$
4 and ${1}/{2}$

Solution:

Let the number be

x

.
According to the question,

x+{1}/{x}={17}/{4}

⇒

{x^{2}+1}/{x}={17}/{4}

⇒

4 x^{2}+4=17 x

⇒

4 x^{2}-17 x+4=0

⇒

4 x^{2}-16 x-1 x+4=0

4 x(x-4)-1(x-4)=0

(4 x-1)(x-4)=0

x={1}/{4}, 4

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