SSC CHSL 19 Apr 2021 Shift 3 Paper

According to the given bar graph, Per cent of failed students in
Class $\mathit{A}=\frac{\left(58-43\right)}{58}\times 100=25.86\%$
Per cent of failed students in
Class B $=\frac{\left(65-45\right)}{65}\times 100=30.77\%$
Per cent of failed students in
Class $\mathit{C}=\frac{\left(62-58\right)}{62}\times 100=6.45\%$
and per cent of failed students in
Class $\mathit{D}=\frac{\left(67-61\right)}{67}\times 100=8.96\%$
$\therefore$ Percentage of failed students is maximum in Class B.