SSC CHSL 17 Mar 2020 Shift 3 Paper

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Question : 73 of 100

Marks: +1, -0

What is the area of a triangle whose sides measure

5 {\cm}, 6 {\cm}

and

7 {\cm}

?

$10.9797 {\cm}^{2}$
$12.8484 {\cm}^{2}$
$16.4545 {\cm}^{2}$
$14.6969 {\cm}^{2}$

Solution:

Here,

a=5 {\cm}, b=6 {\cm}, c=7 {\cm}

Semi perimeter

(s)

={a+b+c}/{2}={5+6+7}/{2}

={18}/{2}=9 {\cm}

Area of triangle,

\A=\√{s(s-a)(s-b)(s-c)}

[by Heron's formula]

\A=\√{9(9-5)(9-6)(9-7)}

\A=\√{9 ×4 ×3 ×2}

\A=6 \√{6}

\A=14.6969 {\cm}^{2}

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