SSC CHSL 17 Mar 2020 Shift 2 Paper

Question : 68 of 100

Marks: +1, -0

P and Q can finish a work in 10 days and 5 days, respectively. Q worked for 2 days and left the job. In how many days can

{\P}

alone finish the remaining work?

Solution:

1 day work of

\P={1}/{10}

1 day work of

\Q={1}/{5}

2 days work of both P and Q

=2({1}/{10}+{1}/{5})=2({3}/{10}\)={6}/{10}={3}/{5}

Remaining work

=1-{3}/{5}={2}/{5}

Now, remaining work will be completed by P.
∴ Time taken by

\P={({2}/{5})}/{({1}/{10})}=4

days

Go to Question:

Prev Question

Next Question