SSC CHSL 16 Apr 2021 Shift 2 Paper

Section: Quantitative Aptitude

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Question : 68 of 100

Marks: +1, -0

If decreasing 180 by

x \%

gives the same result as increasing 60 by

x \%

, then

x \%

of 410 will be more than

(x+20) \%

of 210 (correct to two decimal places) by

$36.57 \%$
$37.57 \%$
$31.67 \%$
$39.46 \%$

Solution:

According to the question,

180 ×[\;{(100-x)}/{100}]=60 ×[\;{(100+x)}/{100}]

⇒ 18000-180 x=6000+60 x

⇒ \;\; 180 x+60 x=18000-6000

⇒ \;\; 240 x=12000

⇒ \;\; x=\;{12000}/{240}=50 \%

∴ x \% \;\text " of "\; 410=50 \% \;\text " of "\;

\;\;\;\;\; 410=\;{1}/{2} × 410=205

\;\text " and "\;(x+20) \% \;\text " of "\; 210

\;\;\; =70 \% \;\text " of "\; 210=\;{70}/{100} × 210=147

∴

Required percentage increase

=\;{(205-147)}/{147} × 100=39.46 \%

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