SSC CHSL 16 Apr 2021 Shift 2 Paper

Section: Quantitative Aptitude

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Question : 55 of 100

Marks: +1, -0

The value of

(5 \;{5}/{6} ÷ 3 \;{1}/{2}

of

\;{10}/{21})

÷(\;{3}/{4} ÷ 1 \;{1}/{2}

of

\;{4}/{5}-\;{4}/{5} × \;{1}/{2})

of

\;{35}/{18}

is

$3 \;{1}/{2}$
$1 \;{4}/{5}$
6
8

Solution:

Given,

(5 \;{5}/{6} ÷ 3 \;{1}/{2}

of

\;{10}/{21})

÷(\;{3}/{4} ÷ 1 \;{1}/{2} \;\text " of "\; \;{4}/{5}-\;{4}/{5} × \;{1}/{2}) \;\text " of "\; \;{35}/{18}

Solve by using BODMAS rule ,

\;\; =(\;{35}/{6} ÷ \;{7}/{2} \;\text " of "\; \;{10}/{21}) ÷(\;{3}/{4} ÷ \;{3}/{2} \;\text " of "\; \;{4}/{5}-\;{4}/{5} × \;{1}/{2})

\;\; =(\;{35}/{6} × \;{3}/{5}) ÷(\;{3}/{4} × \;{5}/{6}-\;{2}/{5}) \;\text " of "\; \;{35}/{18}

\;\; =\;{7}/{2} ÷(\;{5}/{8}-\;{2}/{5}) \;\text " of "\; \;{35}/{18}

\;\; =\;{7}/{2} ÷(\;{25-16}/{40}) \;\text " of "\; \;{35}/{18}

\;\; =\;{7}/{2} ÷ \;{9}/{40} \;\text " of "\; \;{35}/{18}

\;\; =\;{7}/{2} ÷ \;{7}/{16}=\;{7}/{2} × \;{16}/{7}=8

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