SSC CHSL 15 Oct 2020 Shift 3 Paper

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Question : 64 of 100

Marks: +1, -0

If

\tan ^{2} x-3 \sec ^{2} x+3=0

, then the value of

x(0 \≤x \≤90°)

is

$60°$
$0°$
$30°$
$45°$

Solution:

Given,

\tan ^{2} x-3 \sec ^{2} x+3=0

⇒

\tan ^{2} x-3(1+\tan ^{2} x)+3=0

⇒

\tan ^{2} x-3-3 \tan ^{2} x+3=0

⇒

-2 \tan ^{2} x=0

⇒

\tan ^{2} x=0

\⇒\tan x=0

⇒

x=0° (

since,

.0 \≤x \≤90°)

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