9/{cosec 2\theta} + 4 \cos^ 2\theta + 5/{1+\tan^2\theta}

SSC CHSL 15 Nov 2015 Shift 2 Paper

Question : 112 of 200

Marks: +1, -0

9/{cosec 2θ} + 4 cos^ 2θ + 5/{1+tan^2θ}

Solution:

Expression :

9/{cosec 2θ} + 4 cos^ 2θ + 5/{1+tan^2θ}

9sin ^2θ + 4 cos ^2θ +5/{sec^2 θ}

9sin ^2θ + 4 cos ^2θ + 5cos^2 θ

9sin^ 2θ + 9cos^2 θ

9(sin^ 2θ + cos ^2θ) = 9

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