SSC CHSL 15 Nov 2015 Shift 2 Paper

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Question : 107 of 200

Marks: +1, -0

∠A of ∆ABC is a right angle. AD is perpendicular on BC. If BC=14cm and BD=5cm, then measure of AD is :

$√5$ cm
$3√5$ cm
$3.5√5$ cm
$2 √5$ cm

Solution:

Given : BC = 14 cm and BD = 5 cm
⇒

CD = 14-5=9cm

Also,

(AD)^2 = BD × CD

⇒

(AD)^2 = 5 × 9 = 45

⇒

AD = √45

⇒

AD = 3√5

cm

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