SSC CHSL 15 Nov 2015 Shift 1 Paper

Question : 148 of 199

Marks: +1, -0

In ∆ ABC, the external bisectors of the angles ∠b and ∠c meet at the point O. If ∠A = 70° , then themeasure of ∠BOC is:

Solution:

Given : O is excentre of ∆ABC and ∠A = 70°
To find : ∠BOC = θ = ?
Solution : Excentre of a triangle =

90°-1/2×

(Angle opposite to it)
⇒

θ = 90° − ∠A/2

⇒

θ = 90° − 70°/2

⇒

θ = 90° − 35° = 55°

Go to Question:

Prev Question

Next Question