SSC CHSL 15 Nov 2015 Shift 1 Paper

Question : 116 of 199

Marks: +1, -0

The angle of depression of a point situated at a distance of 70 m form the base of a tower is . The height of tower is:

Solution:

AB is the tower = = ?
In ∆ABC,
⇒

tan(60°) ={AB}/ {BC}

⇒

√3 = h/70

⇒

h = 70√3

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