SSC CHSL 13 Apr 2021 Shift 3 Paper

Section: Quantitative Aptitude

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Question : 75 of 100

Marks: +1, -0

A person moved from Place

A

for Place

B

at

2 {pm}

at a speed of

4.5 {km} \/ {h}

, stayed at place

B

for

1.5 {h}

and returned to Place

A

at a speed of

6 {km} \/ {h}

. He came back to Place

A

at

7 {pm}

. What is the distance between Places

A

and

B

(in

{km}

)?

$8 \;{1}/{3}$
$8 \;{2}/{5}$
9
$9 \;{6}/{11}$

Solution:

Let the distance between

A

and

B

be

x {km}

.
We know that,

t=\;{d}/{s}

According to the question,

⇒ \;\; \;{x}/{4.5}+1.5+\;{x}/{6}=5

⇒ \;\; \;{2 x}/{9}+\;{x}/{6}=5-1.5

⇒ \;\; \;{4 x+3 x}/{18}=3.5

∴ \;\; x=\;{3.5 × 18}/{7}=9 {km}

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