The value of \binom{12.5+\frac{4}{7} \text{ of } 56-12}/{(207 \div 23 \times 4.5)-21 \frac{1}{3} \times(\frac{1}{4}+\frac{1}{8})} \text{ is }

SSC CHSL 13 Apr 2021 Shift 3 Paper

Section: Quantitative Aptitude

Question : 62 of 100

Marks: +1, -0

The value of

\;{12.5+{4}/{7} \;\text " of "\; 56-12}/{(207 ÷ 23 × 4.5)-21 \;{1}/{3} ×(\;{1}/{4}+\;{1}/{8})} \;\text " is "\;

Solution:

\;{7}/{(207 ÷ 23 × 4.5)-21 \;{1}/{3} ×(\;{1}/{4}+\;{1}/{8})}

=\;{12.5+32-12}/{40.5-\;{64}/{3} × \;{3}/{8}}=\;{32.5}/{40.5-8}=\;{32.5}/{32.5}=1

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