SSC CHSL 12 Oct 2020 Shift 3 Paper

Question : 46 of 100

Marks: +1, -0

Four letter-clusters have been given, out of which three are alike in some manner and one is different.
Select the odd letter-cluster.

Solution:

As,

\D↖{4}, \L↖{12},\P↖{16}

\←

alphabetical position
⇒

4+12=16

\J↖{10},\P↖{16},\Z↖{26}

\←

alphabetical position
⇒

6+8=14

But,

\M↖{13},\Q↖{17},\S↖{19}

\←

alphabetical position
⇒

13+17 \≠19=30

∴ MQS is the add one out.

Go to Question:

Prev Question

Next Question