SSC CHSL 12 Oct 2020 Shift 2 Paper

Question : 37 of 100

Marks: +1, -0

In a certain code language, 'NIB' is coded as '112' and 'COB' is coded as ' 122 '. How will 'JET' be coded as in that language?

Solution:

As, NIB

=(13+18+25) \×2

⇒

56 \×2=112

(

\∵

taken Reverse alphabetical position) and

{\COB}=(24+12+25) \×2

⇒

61 \×2=122

(

\∵

taken Reverse alphabetical position)Similarly, JET

=(17+22+7) \×2

⇒

46 \×2=92

Reverse alphabetical position
∴

{\JET}=92

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