SSC CHSL 12 Aug 2021 Shift 3 Paper

Section: Quantitative Aptitude

Question : 64 of 99

Marks: +1, -0

Two equal circles of radius

8 {cm}

intersect each other such that each passes through the centre of the other. The length of the common chord is

Solution:

Given,

O O^{'}=8 {cm}

△ A O B

A B^{2} \;\; =(8)^{2}-(4)^{2}=64-16=48

A B \;\; =4 √{3} {cm}

∴

Length of common chord

=2 × 4 √{3}=8 √{3} {cm}

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