SSC CHSL 11 Jan 2017 Shift 2 Paper

Question : 87 of 100

Marks: +1, -0

1/(secA + tanA) is equal to

Solution:

Expression : 1/(secA + tanA)
=

1/{1/{cosA}+{sinA}/{cosA}}

1/{{1+{sinA}}/{cosA}}={cosA}/{1+sinA}

Multiplying both numerator and denominator by

(1 − sinA)

{cosA}/{1+sinA}×{1-{sinA}}/{1-sinA}

{cosA(1-sinA)}/{1-sin^2A}={cosA(1-sinA)}/{cos^2A}

{1-sinA}/{cosA}={1/{cosA}}-{sinA}/{cosA}

secA − tanA

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