SSC CHSL 11 Aug 2021 Shift 2 Paper

Section: Quantitative Aptitude

Question : 66 of 100

Marks: +1, -0

a-\frac{24}{a}=5

, where

a>0

, then the value of

a^{2}+\frac{64}{a^{2}}

Solution:

Given,

\;\; a-\;{24}/{a}=5

⇒ \;\; \;\; a^{2}-5 a-24=0

⇒ \;\; a^{2}-8 a+3 a-24=0

⇒ \;\; a(a-8)+3(a-8)=0

⇒ \;\; (a-8)(a+3)=0

⇒ \;\; a=8

and

-3

Since, a >

\;\;

(given),

\;\; a=8

Now, the value of

\;\; a^{2}+\;{64}/{a^{2}}=(8)^{2}+\;{64}/{(8)^{2}}

=64+1=65

Go to Question:

Prev Question

Next Question