SSC CHSL 10 Jan 2017 Shift 3 Paper

Question : 85 of 100

Marks: +1, -0

(cosecA - sinA)(secA - cosA)(tanA + cotA) is equals to

Solution:

Expression : (cosecA - sinA)(secA - cosA)(tanA + cotA)
=

(1/{sinA}-sinA)(1/{cosA-cosA})

({sinA}/{cosA}+{cosA}/{sinA})

({1-sin^2A}/{sin A}) ({1−cos^2 A}/ {sinAcosA})

({sin^2A + cos^2A}/{sinAcosA})

Using,

({sin^2A + cos^2A=1})

{cos^2A}/{sinA}×{sin^2A}/{cosA}

×1/{sinAcosA}

{sin^2Acos^2A}/{sin^2Acos^2A}=1

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