SSC CHSL 10 Jan 2017 Shift 3 Paper

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Question : 79 of 100

Marks: +1, -0

If

16qxy=(2x+y)^2-(2x-y)^2

, then what is the value of q?

0.5
0.25
4
2

Solution:

Expression :

16qxy=(2x+y)^2-(2x-y)^2

R.H.S. =

(2x+y)^2-(2x-y)^2

=

(4x^2 + y^2 + 4xy)

− (4x^2 + y^2 − 4xy)

=

(4x^2 − 4x^2 ) + (y^2 − y^2 2)

+ (4xy + 4xy)

=

8xy

L.H.S. =

16qxy

⇒

16q = 8

⇒

q = 8 /16 =0.5

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