SSC CHSL 10 Jan 2017 Shift 1 Paper

Question : 66 of 100

Marks: +1, -0

What is the distance between the points (4,7) and (-1,-5)?

Solution:

Distance between two points

(x_1,y_1)

and

(x_2,y_2)

√{(y_2-y_1)^2+(x_2-x_1)^2}

Now, distance between points (-1,-5) and (4,7)
=

√{(7 + 5)^2 + (4 + 1)^2}

√{(12)^2 + (5)^2 }

√{144 + 25}= √169

= 13 units

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