SSC CHSL 10 Jan 2017 Shift 1 Paper

Question : 61 of 100

Marks: +1, -0

Chords PQ and RS of a circle extended externally intersect at point T. Length of the segment PT, if lengths of QT, RT and ST are 9 cm, 18 cm and 6 cm respectively, is

18 cm
16 cm
9 cm
12 cm

Validate

Solution:

Given : QT = 9 cm , RT = 18 cm and ST = 6 cm
To find : PT = ?
Solution : Using properties of secant in circle
⇒

(PT) × (QT) = (RT) × (ST)

⇒

(PT) × 9 = 18 × 6

⇒

PT=108/9=12

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