SSC CHSL 10 Jan 2017 Shift 1 Paper

Question : 53 of 100

Marks: +1, -0

If 2cosAsinB = x, then the value of x is?

Solution:

Expression :

2cosAsinB = x

cosAsinB + cosAsinB

Adding and subtracting

(sinAcosB)

(sinAcosB + cosAsinB)

+ (cosAsinB − sinAcosB)

(sinAcosB + cosAsinB)

− (sinAcosB − cosAsinB)

sin(A + B) − sin(A − B)

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