SSC CHSL 10 Jan 2017 Shift 1 Paper

Let cost price of the machine = Rs.$\mathit{x}$ lakhs
When selling price = Rs. 51 lakhs
⇒ Loss = Rs.$\left(\mathit{x}-51\right)$ lakhs
If selling price = Rs. 60 lakhs
⇒ Profit = Rs.$\left(60-\mathit{x}\right)$ lakhs
According to ques, Profit = 8 × loss
⇒ $\left(60-\mathit{x}\right)=8\times \left(\mathit{x}-51\right)$
⇒ $60-\mathit{x}=8\mathit{x}-408$
⇒ $8\mathit{x}+\mathit{x}=408$ $+60=468$
⇒ $\mathit{x}=\frac{468}{9}=$ Rs. lakhs