SSC CHSL 10 Aug 2021 Shift 1 Paper

Section: Quantitative Aptitude

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Question : 70 of 100

Marks: +1, -0

In

△ A B C, A D

is the internal bisector of

∠ A

meeting

B C

at

D

. If

B D=3.6 {cm}

and

B C=8 {cm}

, then the ratio of

A B

to

A C

will be

$11: 9$
$7: 13$
$13: 7$
$9: 11$

Solution:

Given,

C D \;\; =B C-B D

\;\; =8-3.6=4.4 {cm}

Since,

△ A B D ∼ △ A C D

∴ \;\; \;{A B}/{A C} \;\; =\;{B D}/{C D}=\;{3.6}/{4.4}=\;{36}/{44}

\;\; =9: 11

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