16 \frac{1}{4} \div[2 \frac{1}{6}+\{4 \frac{1}{3}-(2 \frac{1}{2}+\frac{3}{4})\}] is equal to

SSC CHSL 10 Aug 2021 Shift 1 Paper

Section: Quantitative Aptitude

Question : 58 of 100

Marks: +1, -0

16 \;{1}/{4} ÷[2 \;{1}/{6}+\{4 \;{1}/{3}-(2 \;{1}/{2}+\;{3}/{4})\}]

is equal to

Solution:

Given,

16 \;{1}/{4} ÷[2 \;{1}/{6}+\{4 \;{1}/{3}-(2 \;{1}/{2}+\;{3}/{4})\}]

Solving by BODMAS rule,

\;\; =\;{65}/{4} ÷[\;{13}/{6}+\{\;{13}/{3}-(\;{5}/{2}+\;{3}/{4})\}]

\;\; =\;{65}/{4} ÷[\;{13}/{6}+\{\;{13}/{3}-\;{13}/{4}\}]

\;\; =\;{65}/{4} ÷[\;{13}/{6}+\;{13}/{12}]

\;\; =\;{65}/{4} ÷ \;{39}/{12}=\;{65}/{4} × \;{12}/{39}=5

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